Help with screen command

I am trying to use the screen program to sequence the following bash scripts

Can someone help me correct this like so when i execute it on a command line it will execute the screen command on scripts 22 through 25. Thanks for your help.

screen -4 -d -m -S script_worker{22…25} /backend/production/script_worker{22…25}.sh

must do script;
for i in {22…25}
{
screen -4 -d -m -S script_worker$i /backend/production/script_worker$i.sh
}
with 2 dots “. .” not 3

Thank you :slight_smile:

Hello,
I am having trouble running the screen command using bash:
Here is the script contained in test.sh
-----------------------------------------------
#!/usr/bin/env bash
shopt -s nullglob
for i in {$1..$2} {
    /usr/bin/screen -4 -d -m -S script_worker$i /backend/production/script_worker$i.sh
}
-----------------------------------------------

from the command prompt if i issue the following bash command:
>bash test.sh 21 25

I get the following error:
------------------------------
test.sh: line 4: syntax error near unexpected token `/usr/bin/screen'
test.sh: line 4: `    /usr/bin/screen -4 -d -m -S script_worker$i /backend/production/script_worker$i.sh'


Can anyone shed some light on what i am doing wrong?

Thanks for your help.

I figured it out using backward compatible for loops:

#!/usr/bin/env bash
shopt -s nullglob
for ((i=$1;i<=$2;i++))
do
    /usr/bin/screen -4 -d -m -S script_worker$i /backend/production/script_worker$i.sh
done

test:

bash test.sh 01 10